If $2 x^{2} - 11 x + 14 & 3 x^{2} - x - 10$ have common factor find it

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Solution

Factorize both polynomials.

$2 x^{2} - 11 x + 14$
$= 2 x^{2} - 4 x - 7 x + 14$
$= 2 x (x - 2) - 7 (x - 2)$
$= (x - 2) (2 x - 7)$

$3 x^{2} - x - 10$
$= 3 x^{2} - 6 x + 5 x - 10$
$= 3 x (x - 2) + 5 (x - 2)$
$= (x - 2) (3 x + 5)$

Therefore the common factor is $(x - 2)$

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Similar questions

3 x^{2} - x - 10

2 x^{2} - x - 6

x^{2} - 11 x + a = 0

x^{2} - 14 x + 2 a = 0

a

3 x^{2} + 11 x + 10

x^{2} - 11 x + a

x^{2} - 14 x + 2 a

a =

\frac{2 x^{2} - 11 x + 5}{(x - 3) (x^{2} + 2 x + 5)}

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