If 2x2-3xy-y2-x-2y-8-0 then dydx-

The correct option is A 3y 4x 12y 3x+2 2x^2 3xy+y^2+x+2y 8=0 So dydx 4x 3xy' 3y+2y.y'+1+2y'=0 y'( 3x+2y+2)+(4x 3y+1)=0 y'= (4x 3y+ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Higher Order Derivatives

If 2x2-3xy+...

Question

If $2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0$ then $\frac{d y}{d x} =$

\frac{3 y - 4 x - 1}{2 y - 3 x + 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{3 y + 4 x + 1}{2 y + 3 x + 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 y - 4 x + 1}{2 y - 3 x - 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 y - 4 x + 1}{2 y + 3 x + 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

$I f 2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0 t h e n \frac{d y}{d x} =$

(2 y d x + 3 x d y) + 2 x y (3 y d x + 4 x d y) = 0

\frac{d y}{d x} = \frac{4 x - 3 y}{3 x - 2 y}

x + 2 y + 4 z = 2

4 x + 3 y + z = 5

3 x + 2 y + 3 z = 1

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}

\frac{7}{2 x + 3 y} + \frac{4}{3 x - 2 y} = 2

2 x + 3 y \neq 0

3 x - 2 y \neq 0

Join BYJU'S Learning Program