If $2 x - 3 y = 8, 4 x + 3 y = - 2$ , then find the value of $x$ .

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Solution

Given,
$2 x - 3 y = 8 . . . . . (1)$
$4 x + 3 y = - 2 . . . . . (2)$
Adding equation $(1) & (2)$ , we have

$(2 x - 3 y) + (4 x + 3 y) = 8 + (- 2)$
$6 x = 6$
$\Rightarrow x = \frac{6}{6} = 1$

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