If 3-p-7 and -9-q-4- then what is the range of p-q - A- -16-7B- 16-7C- 7-16D- -7-16

The correct option is C (7, 16)3 lt;p lt;7 and 9 lt;q lt; 4 Multiply the second inequality with 1. This causes the sign to flip. So, 3 lt; p l ...

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Standard XII

Mathematics

Properties of inequalities

If 3<p<7 and ...

Question

If $3 < p < 7$ and $- 9 < q < - 4$ , then what is the range of p - q?

(-16, -7)

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(16, 7)

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(7, 16)

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(-7, -16)

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Solution

The correct option is C (7, 16)
$3 < p < 7$ and $- 9 < q < - 4$
Multiply the second inequality with - 1. This causes the sign to flip.
So, $3 < p < 7$ and $4 < - q < 9$
Adding these two inequalities, we get
$7 < p - q < 16$

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If 3<p<7 and −9<q<−4, then what is the range of p - q?

The correct option is C (7, 16)3<p<7 and −9<q<−4 Multiply the second inequality with - 1. This causes the sign to flip. So, 3<p<7 and 4<−q<9 Adding these two inequalities, we get 7<p−q<16

If $3 < p < 7$ and $- 9 < q < - 4$ , then what is the range of p - q?

The correct option is C (7, 16)
$3 < p < 7$ and $- 9 < q < - 4$
Multiply the second inequality with - 1. This causes the sign to flip.
So, $3 < p < 7$ and $4 < - q < 9$
Adding these two inequalities, we get
$7 < p - q < 16$