If 3<p<7 and −9<q<−4, then what is the range of p - q?
A
(-16, -7)
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B
(16, 7)
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C
(7, 16)
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D
(-7, -16)
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Solution
The correct option is C(7, 16) 3<p<7 and −9<q<−4 Multiply the second inequality with - 1. This causes the sign to flip. So, 3<p<7 and 4<−q<9 Adding these two inequalities, we get 7<p−q<16