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Question

If 3 sin xy+4 cos xy=5, then dydx=

(a) -yx

(b) 3 sin xy+4 cos xy3 cos xy-4 sin xy

(c) 3 cos xy+4 sin xy4 cos xy-3 sin xy

(d) none of these

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Solution

(a) -yx

We have, 3 sinxy+4 cosxy=5 3 cosxyxdydx+y-4 sinxyxdydx+y=0 xdydx+y3 cosxy-4 sinxy =0 xdydx+y=0 xdydx=-y dydx=-yx

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