If $30$ mL of $0.5$ M $H_{2} S O_{4}$ diluted to $500$ mL $H_{2} S O_{4}$ , then what will be it's molarity?

0.03 M

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0.3 M

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3 M

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6 M

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Solution

The correct option is A 0.03 M
Volume $V_{1} = 30 m l$

Diluted volume of $H_{2} S O_{4} V_{2} = 500 m l$

Number of moles present in

$1000 m l$ of $0.5 M H_{2} S O = 0.5 m l$

initial molarity $M_{1} = 0.5 M$

We have to find $M_{2}$ (Molarity of $500$ solution)

$M_{2} V_{2} = M_{1} V_{1}$

$M_{2} \times 500 = 0.5 \times 30$

$M_{2} = \frac{15}{500} = 0.03 M$

Hence, the correct option is $A$

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