If 3a52895b7 is exactly divisible by 3 and 11 both, then find the value of a + b. (where a and b are digits from 0 to 9)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D None of these
Divisibility rule of 11:
We must subtract and then add the digits in an alternating pattern from left to right,
if the result is 0 or 11, then the given number is divisible by 11.

Given,

$3 a 52895 b 7$

$= 3 - a + 5 - 2 + 8 - 9 + 5 - b + 7$

$3 + 5 + 8 + 5 + 7 = a + 2 + 9 + b$

$28 = a + b + 11$

$∴ a + b = 17$

Suggest Corrections

Similar questions

If the addition of numbers 2A and 33 gives 5B, where A and B are digits then find A and B. Given that number 2A is divisible by 10.

If the 4-digit number x27y is exactly divisible by 9, then the least value of (x + y) is

(a) 0

(b) 3

(d) 9

f (x) = x^{3} - 6 x^{2} + a x + b

Join BYJU'S Learning Program