If 3x - 7 - 1- where x - Z- then find values of x-

The correct option is B { 2, 3, 4,...} Given, 3x+7 ≤ 1 where x ∈ N 3x ≤ 1 7 x ≤ 63 ⇒ x ≤ 2 Since, the replacement set is set of i ...

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Solving Inequalities

If 3x + 7 ≤...

Question

If $3 x + 7 \leq 1$ , where $x \in Z$ , then find values of $x$ .

{2, 2}

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{- 2, - 3, - 4, . . .}

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{- 2, - 1, 0, 1, . . .}

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None of these

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Solution

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Similar questions

\frac{x^{2} - 3 x + 4}{x^{2} + 3 x + 4}

Consider lines

$L_{1} : \frac{x - 2}{1} = \frac{y - 3}{1} = \frac{z - 4}{- k}$

$L_{2} : \frac{x - 1}{2} = \frac{y - 4}{2} = \frac{z - 5}{1}$

Equation of plane containing these lines is

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & 3 x - 1 & - x + 3 2 x + 1 & 2 + x^{2} & x^{3} - 3 x - 3 & x^{2} + 4 & 3 x \end{matrix} ∣ ∣ ∣ ∣ ∣ = a_{0} + a_{1} x + a_{2} x^{2} + . . . + a_{7} x^{7}

a_{0}

| z - 3 - 4 i |^{2} + | z + 2 - 7 i |^{2} + | z - 5 + 2 i |^{2}

z = x + i y

z

f (z) = \frac{7 - z}{1 - z^{2}}

z = 1 + 2 i

|f (z)|

\frac{|z|}{2}

|z|

2 |z|

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