If (4, 0) and (-4, 0) be the vertices and (6, 0) and (-6, 0) be the foci of a hyperbola, then its eccentricity is

5/2

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Solution

The correct option is C

Vertices $(\pm 4, 0) \equiv (\pm a, 0) \Rightarrow a = 4$
Foci $(\pm 6, 0) \equiv (\pm a e, 0) \Rightarrow e = \frac{6}{4} = \frac{3}{2}$

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