If 4.0 gm $N a O H$ is present in 1 litre solution, then its pH will be:

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Solution

The correct option is B 13
$[N a O H] = 4 / (40 m o l e / l i t r e) = 0.1 M$
$[O H^{-}] = 10^{- 1} M, [H^{+}] = 10^{- 13} M$
$∴ p H = 13$

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