If $\frac{4}{5}, a,$ 2 are three consecutive terms of an AP, find the value of a.

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Solution

If $\frac{4}{5}$ , a and 2 are three consecutive terms of an AP, then we have:
a - $\frac{4}{5}$ = 2 - a
⇒ 2a = 2 + $\frac{4}{5}$
⇒ 2a = $\frac{14}{5}$
⇒ a = $\frac{7}{5}$

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