If $4 a + 5 b + 9 c = 36$ and $7 a + 9 b + 17 c = 66$ , then $a + b + c =$

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Solution

Consider,
$4 a + 5 b + 9 c = 36$ ------ (i)
$7 a + 9 b + 17 c = 66$ ------ (ii)

Multiply (i) by 2, we get
$8 a + 10 b + 18 c = 72$ ------ (iii)

(iii) - (ii) gives,
$a + b + c = 6$

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Similar questions

If 4a+5b+9c=36 and 7a+9b+17c=66 then find the value of a+b+c

- 5 a^{2} + 3 a - 5 b^{2}

7 a^{2} + 4 a - 9 b^{2}

\frac{a}{b} = \frac{7}{3}

\frac{7 a + 9 b}{7 a - 9 b}

(4 a + 9 b) (4 c - 9 d) = (4 a - 9 b) (4 c + 9 d)

a : b = c : d

(7 a - 9 b)

(7 a - 9 b)

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