If $6.022 \times 10^{23}$ molecules of urea are present in $100 m l$ of its solution, then calculate the concentration of the solution (Molecular mass of urea $= 60$ ).

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Solution

$6.022 \times 10^{23}$ molecules
i.e. $1$ mole
$v = 100 m L$
Concentration $= \frac{n o . o f m o l e s}{v o l u m e i n L}$
$= \frac{1}{(100 / 100)} = 10 M$

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