If (6)15×(10)5×(15)6=2x×3y×5z then find the value of x + y + z.
A
26
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B
52
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C
42
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D
48
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Solution
The correct option is D52 (6)15×(10)5×(15)6=2x×3y×5z ⇒(2×3)15×(2×5)5×(3×5)6=2x×3y×5z ⇒2(15+5)3(15+6)5(5+6)=2x×3y×5z ⇒220321511=2x×3y×5z By comparing, x=20.y=21andz=11 x + y + z = 20+21+11=52