Question

If 6 years hence a man's age will be 3 times the age of his son and three years ago he was 9 times as old as his son, then what is the present age of the man?

• A. 25 years
• B. 35 years
• C. 15 years
• D. 30 years

Answer 1

The correct option is D 30 years

Let the present age of man be ‘x’ and the age of his son be ‘y’
6 years hence, (x + 6) = 3 $\times$ (y + 6)
3 years ago, (x - 3) = 9 $\times$ (y - 3)
Solving for x, x= 30yrs