If 64is divided into there parts proportional to 2, 4 and 6, the smallest part is:

5 \frac{1}{3}

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10 \frac{2}{3}

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Solution

The correct option is D $10 \frac{2}{3}$
Let the parts be 2x, 4x and 6x.
Given, 2x+4x+6x=64
Hence 12x=64,
Smallest part 2x will be $\frac{12 x}{6}$ = $\frac{64}{6}$ = $10 \times \frac{2}{3}$

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