Question

If $6y^2+17y+12=0$, then $y=-\frac{4}{3},-\frac{3}{2}$.

• A. Yes
• B. No
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is A Yes

Given equation is, $6y^2+17y+12=0$

$6y^2+9y+8y+12=0$

$3y(2y+3)+4(2y+3)=0$

$(3y+4)(2y+3)=0$

$\therefore y=\frac{-4}{3},\frac{-3}{2}$