Question

If $7\left[\frac{(\frac{5x}{3}-\frac{3}{2})}{2}\right]+\frac{3}{2}=\frac{1}{4}$, then what is the value of $x$?

• A. $\frac{35}{24}$
• B. $\frac{24}{35}$
• C. $-\frac{24}{35}$
• D. $-\frac{35}{24}$

Answer 1

The correct option is B $\frac{24}{35}$

$7\left[\frac{(\frac{5x}{3}-\frac{3}{2})}{2}\right]+\frac{3}{2}=\frac{1}{4}$
$7\left[\frac{10x-9}{2\times 6}\right]+\frac{3}{2}=\frac{1}{4}$
$x=\frac{48}{70}=\frac{24}{35}$.