Question

If $78$ is divided into three parts which are proportional to $1,\frac{1}{2},\frac{1}{6}$, then what is the middle part?

• A. $\frac{28}{3}$
• B. $13$
• C. $\frac{52}{3}$
• D. $\frac{117}{5}$

Answer 1

The correct option is D $\frac{117}{5}$

$1:\frac{1}{2}:\frac{1}{6}=6:3:1$
Middle part $=\frac{3}{10}\times 78=\frac{117}{5}$