Question

If 8.4 g of element X includes $9.03\times {10}^{22}$ atoms and 0.1mol $X_2{Y}_3$ compound is 16g find the atomic mass of element Y. (Avogadro number is $6.02\times {10}^{23})$

• A. Y=16.5g/mol
• B. Y=26g/mol
• C. Y=13.7g/mol
• D. Y=16g/mol

Answer 1

The correct option is D Y=16g/mol

One mole is defined as the amount of substance containing as many elementary entities (atoms, molecules, ions, electrons, radicals, etc.) as there are atoms in 12 grams of carbon-12. The number of particles, that is, atoms, ions and molecules present in one mole of a substance is fixed with a value of $6.022\times {10}^{23}$.

Moles of element X is ;
$nx=(9.03\times {10}^{23}(6.02\times {10}^{23})=0.15mol$
Atomic mass of X;
$A_x=\frac{8.4}{0.15}=56g/mol$
Molar mass of $X_2{Y}_3$ compound;
$M_{X_2{Y}_3}=\frac{16}{0.1}=160g/mol$
We find atomic mass of Y by;
2.X + 3Y =160
2.(56) + 3(Y)=160
Y=16g/mol is atomic mass of Y.