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Question

# If 8.4 g of element X includes 9.03×1022 atoms and 0.1mol X2Y3 compound is 16g find the atomic mass of element Y. (Avogadro number is 6.02×1023)

A
Y=16.5g/mol
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B
Y=26g/mol
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C
Y=13.7g/mol
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D
Y=16g/mol
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Solution

## The correct option is D Y=16g/molOne mole is defined as the amount of substance containing as many elementary entities (atoms, molecules, ions, electrons, radicals, etc.) as there are atoms in 12 grams of carbon-12. The number of particles, that is, atoms, ions and molecules present in one mole of a substance is fixed with a value of 6.022×1023. Moles of element X is ; nx=(9.03×1023(6.02×1023)=0.15mol Atomic mass of X; Ax=8.40.15=56g/mol Molar mass of X2Y3 compound; MX2Y3=160.1=160g/mol We find atomic mass of Y by; 2.X + 3Y =160 2.(56) + 3(Y)=160 Y=16g/mol is atomic mass of Y.

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