Question

If $8$ men can do a piece of work in $15$ days, how many men are required to do same piece of work in $10$ days?

Answer 1

Given that $8$ men can do a piece of work in $15$ days

Assume $x$ men are required to do same piece of work in $10$ days.

As the work is exactly same.

Therefore,

$$\begin{gathered} 8\times 15=x\times 10 \\ x=\frac{8\times 15}{10} \\ x=12men \end{gathered}$$

Hence, $12$ men are required to do same piece of work in $10$ days