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Question

If 8 molecules of ribulose 1, 5- bisphosphate molecules are carboxylated by RUBISCO, how many PGA molecules are ultimately available to PCR cycle in photosynthetic carbon carboxylation cycle?

A
12
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B
16
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C
24
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D
8
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Solution

The correct option is B 16
In normal Calvin cycle, 6 molecules of ribulose 1, 5- bisphosphate molecules is converted to 12 PGA
Thus, 8 molecules of Ribulose 1, 5- bisphosphate molecules is converted to
(8 X 12)/ 6= 16 Phospho glyceric acid.
Thus, the correct answer is option B.

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