Question

If $8$ tins holds $42\frac{2}{3}l$ of oil. How many liters can $1$ such tin hold?

Answer 1

Quantity of oil that $8$ tins can hold $=42\frac{2}{3}l=\frac{128}{3}l$

Quantity of oil that $1$ tin can hold be $x$

$\Rightarrow \frac{x}{1}=\frac{\frac{128}{3}}{8}$

$\Rightarrow x=\frac{128}{3}\times \frac{1}{8}$

$\Rightarrow x=\frac{16}{3}$

$\Rightarrow x=5\frac{1}{3}l$

Hence $1$ tin can hold $5\frac{1}{3}l$ of oil.