If 9/5 of a number exceeds 5/7 of that number by 70, find that number.

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Solution

$D e a r S t u d e n t L e t x b e t h e n u m b e r T h e n \frac{9 x}{5} = \frac{5 x}{7} + 70 \frac{9 x}{5} - \frac{5 x}{7} = 70 \frac{63 x - 25 x}{35} = 70 38 x = 2450 x = \frac{2450}{38} = \frac{1225}{19} = 64.47 R e g a r d s$

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