If $9 x^{2} + 25 y^{2} = 181 a n d x y = - 6, f i n d t h e v a l u e o f 3 x + 5 y .$

Open in App

Solution

$9 x^{2} + 25 y^{2} = 181, a n d x y = - 6 (3 x + 5 y)^{2} = (3 x)^{2} + (5 y)^{2} + 2 \times 3 x + 5 y \Rightarrow 9 x^{2} + 25 y^{2} + 30 x y = 181 + 30 \times (- 6) = 181 - 180 = 1 (3 x + 5 y)^{2} = (\pm 1)^{2} ∴ 3 x + 5 y = \pm 1$

Suggest Corrections

187

Similar questions

If ${9 x}^{2} + {25 y}^{2} = 181$ and xy = - 6. Find the value of 3x + 5y.

3 x + 5 y = 11

x y = 2

9 x^{2} + 25 y^{2}

9 x^{2} + 25 y^{2} = 181 a n d x y = - 6

9 x^{2} + 4 y^{2}

Multiply 9x²+25y²+15xy+12x-20y+16 by 3x-5y-4 using suitable identity

Join BYJU'S Learning Program