If 9x2+25y2=181 and xy=−6, find the value of 3x+5y.
As we know that (a+b)2=a2+b2+2ab
(3x+5y)2=9x2+25y2+2×3x×5y
(3x+5y)2=181−180=1
(3x+5y)=√1
so (3x+5y)=1 is Ans.
If 9x2+25y2=181 and xy = - 6. Find the value of 3x + 5y.
Multiply 9x²+25y²+15xy+12x-20y+16 by 3x-5y-4 using suitable identity