Question

If A (1, –1), B (0, 4), C (–5, 3) are vertices of a triangle then find the slope of each side.

Answer 1

A (1, –1), B (0, 4), C (–5, 3) form a triangle.
Slope of AB = $\frac{4-\left(-1\right)}{0-1}=\frac{5}{-1}=-5$
Slope of BC = $\frac{3-4}{-5-0}=\frac{-1}{-5}=\frac{1}{5}$
Slope of AC = $\frac{3-\left(-1\right)}{-5-1}=\frac{4}{-6}=\frac{-2}{3}$