If a1,a2,a3,a4 are in AP, then
a1+a4=a2+a3
a1+a2=a2+a3
a1+a2=a3+a4
a1+a3=a2+a4
The sum of the first term and the last term are equal to the sum of the second term and the second last term and so on. Hence, here a1+a4=a2+a3
If a1,a2,a3,a4 are the coefficients of any four
consecutive terms in the expansion of (1+x)n, then
a1a1+a2 + a3a3+a4 =