CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Common Difference

If a 1, a 2, ...

Question

If $a_{1}, a_{2}, a_{3}, a_{4}$ are in AP, then

A

$a_{1} + a_{4} = a_{2} + a_{3}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

$a_{1} + a_{2} = a_{2} + a_{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

$a_{1} + a_{2} = a_{3} + a_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

$a_{1} + a_{3} = a_{2} + a_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$a_{1} + a_{4} = a_{2} + a_{3}$

In an AP, the sum of the first term and the last term is equal to the sum of the second term and the second last term of the AP and so on.
Hence, here $a_{1} + a_{4} = a_{2} + a_{3}$

Suggest Corrections

thumbs-up

0

Similar questions

a_{1}, a_{2}, a_{3}, a_{4}

are terms of an AP, then the relation between them is

If $a_{1}, a_{2}, a_{3}, a_{4}$ are the coefficients of any four

consecutive terms in the expansion of ( $1 + x)^{n}$ , then

$\frac{a_{1}}{a_{1} + a_{2}}$ + $\frac{a_{3}}{a_{3} + a_{4}}$ =

a_{1}, a_{2}, a_{3}, a_{4}, a_{5} > 0

\frac{a_{1}}{a_{2} + a_{3}} + \frac{a_{2}}{a_{3} + a_{4}} + \frac{a_{3}}{a_{4} + a_{5}} + \frac{a_{4}}{a_{5} + a_{1}} + \frac{a_{5}}{a_{1} + a_{2}} \geq \frac{5}{2}

a_{1}, a_{2}, a_{3}, a_{4}, . . {. ., a}_{20}

a_{1} + a_{20} = 45

a_{1} + a_{2} + a_{3} + a_{4}, . . {. . + a}_{20}

a_{1}, a_{2}, a_{3}, a_{4}

are in AP, then

\frac{1}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{1}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{1}{\sqrt{a_{3}} + \sqrt{a_{4}}}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Introduction to AP

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Common Difference

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon