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Question

If a=1+j+2k and b=3i+j+k then the value of a×b is-

A
i+5j2k
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B
2i+7j+2k
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C
3i+7j2k
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D
i5j+5k
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Solution

The correct option is A i+5j2k
a=^i+^j+2^k and b=3^i+^j+^k
a×b=(^i+^j+2^k)×(3^i+^j+^k)
a×b=(^i×3^i)+(^i×^j)+(^i×^k)+(^j×3^i)+(^j×^j)+(^j×^k)+(2^k×3^i)+(2^k×^j)+(2^k×^k)
a×b=0+^k^j3^k+0+^i+6^j2^i+0
a×b=^k^j3^k+^i+6^j2^i
a×b=^i+5^j2^k
Hence the correct option is (A).

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