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Question

If$ a + 10o, 3a + 10o, 5a - 10o and 3a - 10o are the angles of a quadrilateral, then what is the value of a?


A

50o

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B

40o

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C

20o

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D

30o

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Solution

The correct option is

C

30o



Given, a + 10o, 3a + 10o, 5a - 10o , 3a - 10o are the angles of a quadrilateral.

We know that the sum of angles of a quadrilateral is 360o.

Therefore,

a + 10o+3a + 10o+ 5a - 10o + 3a - 10o = 360o

12a = 360o

a=36012

a=300


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