If$ a + 10o, 3a + 10o, 5a - 10o and 3a - 10o are the angles of a quadrilateral, then what is the value of a?
The correct option is
C
30o
Given, a + 10o, 3a + 10o, 5a - 10o , 3a - 10o are the angles of a quadrilateral.
We know that the sum of angles of a quadrilateral is 360o.
Therefore,
a + 10o+3a + 10o+ 5a - 10o + 3a - 10o = 360o
⇒12a = 360o
⇒a=36012
⇒a=300