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Standard VII

Mathematics

Dividing a Monomial by a Monomial

If A= 10W3+2...

Question

If A= $10 W^{3} + 20 W^{2} - 55 W + 60,$
$B = - 25 W^{2} + 15 W - 10$ and $C = 5 W^{2} - 10 W + 20,$ then A+B-C is equal to -

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Solution

$A = 10 w^{3} + 20 w^{2} - 55 w + 60$
$B = - 25 w^{2} + 15 w - 10$
$C = 5 w^{2} - 10 w + 20$
$A + B - C = 10 w^{3} - 5 w^{2} - 40 w + 50 - 5 w^{2} + 100 w - 20$
$= 10 w^{3} - 10 w^{2} - 30 w + 30$
$= 10 w^{2} (w - 1) - 30 (w - 1)$
$A + B - C = 10 (w^{2} - 3) (w - 1)$

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Q. Question 4
In the figure, if

∠ A B C = 20^{\circ}

, then

∠ A O C

is equal to

(A)

20^{\circ}

(B)

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(C)

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(D)

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Q. Question 4
In the figure, if

∠ A B C = 20^{\circ}

, then

∠ A O C

is equal to

(A)

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(B)

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(C)

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Q. Question 4
In the figure, if

∠ A B C = 20^{\circ}

, then

∠ A O C

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(A) 20º
(B) 40º
(C) 60º
(D) 10º

5 %

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income of C. If the income of C is Rs.

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If A=10W3+20W2−55W+60,B=−25W2+15W−10 and C=5W2−10W+20, then A+B-C is equal to -

A=10w3+20w2−55w+60B=−25w2+15w−10C=5w2−10w+20A+B−C=10w3−5w2−40w+50−5w2+100w−20 =10w3−10w2−30w+30 =10w2(w−1)−30(w−1)A+B−C=10(w2−3)(w−1)

If A= $10 W^{3} + 20 W^{2} - 55 W + 60,$
$B = - 25 W^{2} + 15 W - 10$ and $C = 5 W^{2} - 10 W + 20,$ then A+B-C is equal to -

$A = 10 w^{3} + 20 w^{2} - 55 w + 60$
$B = - 25 w^{2} + 15 w - 10$
$C = 5 w^{2} - 10 w + 20$
$A + B - C = 10 w^{3} - 5 w^{2} - 40 w + 50 - 5 w^{2} + 100 w - 20$
$= 10 w^{3} - 10 w^{2} - 30 w + 30$
$= 10 w^{2} (w - 1) - 30 (w - 1)$
$A + B - C = 10 (w^{2} - 3) (w - 1)$