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Question

If A(1,2,1)B(3,5,0)C(5,11,22) and D(5,8,6) are the vertices. Find the volume of the parallelepiped with segment AB,AC and AD as concurrent edges.

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Solution

Volume of parallelopiped is AB.(AC×AD)
now
AB=(31)ˆi+(52)ˆj+(0(1))ˆk=2ˆi+3ˆj+1ˆkAC=(51)ˆi+(112)ˆj+(22(1))ˆk=4ˆi+9ˆj+23ˆkAD=(51)ˆi+(82)ˆj+(6(1))ˆk=4ˆi+6ˆj+7ˆk
so volume of the parallelopiped is
(2ˆi+3ˆj+ˆk).((4ˆi+9ˆj+23ˆk)×(4ˆi+6ˆj+7ˆk))=(2ˆi+3ˆj+ˆk).((63138)ˆi+(28+92)ˆj+(2436)ˆk)=(2ˆi+3ˆj+ˆk).(75ˆi+ˆ64j12ˆk)=|150+19212|=30

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