If a 1 x - b 1 y - c 1-0- a 2 x - b 2 y - c 2-0 are two equations with an unique solution- thena 1- a 2- b 1- b 2- c 1- c 2A- FalseB- True

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Byju's Answer

Standard X

Mathematics

Comparing the Ratios of Coefficients of a Linear Equation

If a 1 x + b ...

Question

If $a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with an unique solution, then
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$

True

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False

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Solution

The correct option is B
False

If $a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with a unique solution(consistent), then
$\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$

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If a1x+b1y+c1=0, a2x+b2y+c2=0 are two equations with an unique solution, then a1a2=b1b2=c1c2

The correct option is B False If a1x+b1y+c1=0, a2x+b2y+c2=0 are two equations with a unique solution(consistent), then a1a2≠b1b2

If $a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with an unique solution, then
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$

The correct option is B
False

If $a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with a unique solution(consistent), then
$\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$