If a ^2/3 - b^2/3- c^213 = 0, then the value of (a^2-b^2 -c^2) is (1) 3a^2/3. b^2/3 .c^2/3 (3) 27a^2b^2c^2 (2) 27a^2/3. b^2/3. c2/3 (4) 3a²b^2c^2

Open in App

Solution

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ ∣ \begin{matrix} - a^{2} & a b & a c a b & - b^{2} & b c a c & b c & - c^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ + ∣ ∣ ∣ ∣ ∣ \begin{matrix} a^{2} & - b^{2} & - c^{2} - a^{2} & b^{2} & - c^{2} - a^{2} & - b^{2} & c^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ =

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

\frac{(b^{2} + c^{2})}{3 b c} + \frac{(c + a)^{2}}{3 a c} + \frac{(a + b)^{2}}{3 a b} = \frac{1}{3}

a + b + c = 0

\frac{1}{b^{2} + c^{2} - a^{2}} + \frac{1}{c^{2} + a^{2} - b^{2}} + \frac{1}{a^{2} + b^{2} - c^{2}}

\frac{a^{2} - {(b - c)}^{2}}{{(a + c)}^{2} - b^{2}} + \frac{b^{2} - {(a - c)}^{2}}{{(a + b)}^{2} - c^{2}} + \frac{c^{2} - {(a - b)}^{2}}{{(b + c)}^{2} - a^{2}}

Join BYJU'S Learning Program