If a2 - b2 -1- then 1 - b - ia-1 - b - ia -

The correct option is C b + iaGiven that a^2 + b^2 = 1 #160; ∴1 + b +ia/1 + b ia = (1 + b + ia)(1 + b + ia)/(1 + b ia)(1 + b + ia) #160; # ...

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Complex Numbers

If a2 + b2 ...

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If $a^{2} + b^{2} = 1$ , then $\frac{1 + b + i a}{1 + b - i a} =$

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b + ia

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a + ib

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