Question

# If $$a^2+b^2+c^2=250$$ and $$ab+bc+ca=3$$, then find $$a+b+c$$.

Solution

## $$a^{2}+b^{2}+c^{2}= 250$$ & $$ab+bc+ac= 3$$, find $$a+b+c$$$$\rightarrow$$ the general formula$$(a+b+c)^{2}= a^{2}+b^{2}+c^{2}+2(ab+bc+ac)$$$$= 250+2(3)$$$$= 250+6$$$$\therefore (a+b+c)^{2}= 256$$$$\therefore a+b+c= \sqrt{256}$$$$\therefore a+b+c= 16$$Mathematics

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