If a2-b2-c2-250 and a b-b c-c a-3 then find the value of a-b-c

Given: a² + b² + c² = 250 and ab + bc + ca = 3. Now, using (a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca. – gt; (a+b+c)² = a² + b² + c² + 2(ab + bc + ca) – g ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Expansion of (x^2 - y^2)

If a2+b2+c2=2...

Question

If a²+b²+c²=250 and ab +bc+ca =3 then find the value of a+b+c

Open in App

Solution

Given: a² + b² + c² = 250 and ab + bc + ca = 3.
Now, using (a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca.
--> (a+b+c)² = a² + b² + c² + 2(ab + bc + ca)
--> (a+b+c)² = 250 + 2(3) = 256
--> (a+b+c)² = 256
--> (a+b+c) = √256
--> a+b+c = ±16 (± means "positive and negative")

Suggest Corrections

Similar questions

Q. If

a^{2} + b^{2} + c^{2} = 250

and

a b + b c + c a = 3

, then find

a + b + c

Q2. if a2 +b2+c2=250 and ab+bc+ca=3 find a+b+c

If a = 1, b = -2 and c = 3 then find the value of a $^{2}$ +b $^{2}$ +c $^{2}$ +ab+bc+ca.

If $a + b + c = 0$ then find value of $\frac{a^{2}}{b c} + \frac{b^{2}}{a c} + \frac{c^{2}}{a b}$

Q. If a+b+c=0 what is the value of

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

Join BYJU'S Learning Program

If a2+b2+c2=250 and ab +bc+ca =3 then find the value of a+b+c

Given: a² + b² + c² = 250 and ab + bc + ca = 3. Now, using (a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca. --> (a+b+c)² = a² + b² + c² + 2(ab + bc + ca) --> (a+b+c)² = 250 + 2(3) = 256 --> (a+b+c)² = 256 --> (a+b+c) = √256 --> a+b+c = ±16 (± means "positive and negative")

If a²+b²+c²=250 and ab +bc+ca =3 then find the value of a+b+c

Given: a² + b² + c² = 250 and ab + bc + ca = 3.
Now, using (a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca.
--> (a+b+c)² = a² + b² + c² + 2(ab + bc + ca)
--> (a+b+c)² = 250 + 2(3) = 256
--> (a+b+c)² = 256
--> (a+b+c) = √256
--> a+b+c = ±16 (± means "positive and negative")