If a=2012,b=2011,c=2010 then the value of a2+b2+c2−ab−bc−ca is
A
0
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B
2012
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C
3
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D
4024
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Solution
The correct option is B3 Let a=2012,b=2011,c=2010 x=a2+b2+c2−ab−bc−ca 2x=2(a2+b2+c2−ab−bc−ca) ⇒2x=2a2+2b2+2c2−2ab−2bc−2ca ⇒2x=a2−2ab+b2+b2−2bc+c2+c2−2ca+a2 ⇒2x=(a−b)2+(b−c)2+(c−a)2 ⇒2x=(2012−2011)2+(2011−2010)2+(2010−2012)2 ⇒2x=1+1+4 ⇒x=3