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Question

If a=2012,b=2011,c=2010 then the value of a2+b2+c2−ab−bc−ca is

A
0
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B
2012
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C
3
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D
4024
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Solution

The correct option is B 3
Let
a=2012,b=2011,c=2010
x=a2+b2+c2abbcca
2x=2(a2+b2+c2abbcca)
2x=2a2+2b2+2c22ab2bc2ca
2x=a22ab+b2+b22bc+c2+c22ca+a2
2x=(ab)2+(bc)2+(ca)2
2x=(20122011)2+(20112010)2+(20102012)2
2x=1+1+4
x=3

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