Question

If $a=23,b=27$ and $c=50$, the value of $a^3+b^3-c^3+3abc$ is

• A. $100$
• B. $73$
• C. $77$
• D. $0$

Answer 1

Answer: (D)

$0$

Consider the expression $a^3+b^3-c^3+3abc$ and substitute $a=23,b=27$ and $c=50$ as shown below:

$a^3+b^3-c^3+3abc=(23{)}^3+(27{)}^3-(50{)}^3+(3\times 23\times 27\times 50)=12167+19683-125000+93150$

$=(12167+19683+93150)-125000=125000-125000=0$

Hence, $a^3+b^3-c^3+3abc=0$