If a + 2b + c = 0; then evaluate a3+8b3+c3
a3+8b3+3×a×2b(a+2b)=(−c)3 [∵(a+b)3=a3+b3+3ab(a+b)]
a3+8b3+3×a×2b(−c)=(−c)3 ....... [ from (1)] a3+8b3−6abc=(−c)3 ∴a3+8b3+c3=6abc
Hence the correct answer is option (B).
If a+2b+3c=0,prove that a3+8b3+27c3=18abc