Formula to be used :
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(x + y) ³ = x³ + y³ + 3xy(x+y).
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(a +2b) = 5
Cubing both sides we get,
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
(a +2b) ³ = 5³
or,
(a) ³ + (2b)³ + 3a.2b(a+2b) =125
or,
a³ + 8b³ + 6ab×5 =125
( since a+2b=5)
or,
a³ + 8b³ +30ab = 125 (proved)