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Question

If a=3i^-j^-4k^, b=-2i^+4j^-3k^ and c=i^+2j^-k^, find 3a-2b+4c .

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Solution

Given: a = 3i^ - j^- 4k^, b =-2i^ + 4j^ - 3k^ and c = i^ + 2j^ - k^.

Now, 3a - 2b+ 4c = 33i^ - j^ - 4k^ - 2-2i^ + 4j^ - 3k^ + 4i^ + 2j^ - k^ = 9i^ - 3j^ - 12k^ + 4i^ - 8j^ + 6k^ + 4i^ + 8j^ - 4k^ = 17i^ - 3j^ - 10k^
Hence, 3a - 2b + 4c = 172 + -32 + -102 = 289+9 + 100 = 398

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