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Question

If a =4i^+3j^+k^ and b =i^-2k^, then find 2b^×a .

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Solution

Given:a=4i^+3j^+k^ 2b=2i^+0j^-4k^2b×a=i^j^k^20-4431 =0+12 i^-2+16 j^+6-0k^ =12i^-18j^+6k^2b×a=122+-182+62 =504

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