Question

If a and b are integers such that $a^{2}1>b^2$, then $a^{3}1>b^3$.

• A. True
• B. False
• C. Ambiguous
• D. Insufficient information

Answer 1

Answer: (B)

False

False, since the square of -2 is 4 is greater than the square of 1 i.e. 1, then the cube is -2 is -8 is not greater than the cube of 1 is 1.
$\therefore$ if a and b are integers such that $a^{2}1>b^2$, then $a^{3}1>b^3$ is not true in all cases.