If A and B are mutually exclusive events such that PA-0-4- PB-x and PA- B- 1 2- then the value of 1 x is

Name: JEE- Grade 12- Mathematics- Probability- Session 05- W18
Uploaded: 2022-07-04T10:36:42+05:30
Description: A and B are mutually exclusive events ∴ P(A∩ B )=ϕ P(A∪ B )=P(A)+P(B) 0.5=x+0.4 ∴ x=0.1⇒ 1 x=10 ...

A and B are mutually exclusive events ∴ P(A∩ B )=ϕ P(A∪ B )=P(A)+P(B) 0.5=x+0.4 ∴ x=0.1⇒ 1 x=10 ...

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Standard XII

Mathematics

Mutually Exclusive Events

If A and B ar...

Question

If $A$ and $B$ are mutually exclusive events such that $P (A) = 0.4, P (B) = x$ and $P (A \cup B) = \frac{1}{2},$ then the value of $\frac{1}{x}$ is

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Solution

$A$ and $B$ are mutually exclusive events
$∴ P (A \cap B) = ϕ$
$P (A \cup B) = P (A) + P (B)$
$0.5 = x + 0.4$
$∴ x = 0.1 \Rightarrow \frac{1}{x} = 10$

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Mutually Exclusive Events

Standard XII Mathematics

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If A and B are mutually exclusive events such that P(A)=0.4,P(B)=x and P(A∪B)=12, then the value of 1x is

A and B are mutually exclusive events ∴P(A∩B)=ϕ P(A∪B)=P(A)+P(B) 0.5=x+0.4 ∴x=0.1⇒1x=10

If $A$ and $B$ are mutually exclusive events such that $P (A) = 0.4, P (B) = x$ and $P (A \cup B) = \frac{1}{2},$ then the value of $\frac{1}{x}$ is

$A$ and $B$ are mutually exclusive events
$∴ P (A \cap B) = ϕ$
$P (A \cup B) = P (A) + P (B)$
$0.5 = x + 0.4$
$∴ x = 0.1 \Rightarrow \frac{1}{x} = 10$