If A and B are the angles of a right angled triangle ABC, right angled at C, then 1+cot²A=

cot²B

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tan²B

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cos²B

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sec²B

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Solution

The correct option is D
sec²B

Given, triangle ABC is right angled at C. Therefore,

A+B=90^o

A=90^o-B

1+cot²A=1+cot²(90^o-B)=1+tan²B=sec²B

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Similar questions

If A and B are the angles of a right angled triangle ABC, right angled at C, then 1+cot²A =

△ A B C

∠ A + ∠ C

a, b

c

A B C

c = 2 a

b^{2} - 3 a^{2} = 0

∠ A B C =

△ A B C

cos (A + B) =

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