If A and B are the angles of a right angled triangle ABC, right angled at C, then 1+cot²A =

cot²B

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sec²B

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tan²B

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cos²B

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Solution

The correct option is B
sec²B

Given, triangle ABC is right angled at C. Therefore,

A+B=90^o or A=90^o-B

1+cot²A = 1 + cot²(90^o-B) = 1+tan²B = sec²B

[Since, cot(90^o-) = tan, 1 + tan² = sec²]

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If A and B are the angles of a right angled triangle ABC, right angled at C, then 1+cot2A =

The correct option is B sec2BGiven, triangle ABC is right angled at C. Therefore, A+B=90o or A=90o-B 1+cot2A = 1 + cot2(90o-B) = 1+tan2B = sec2B [Since, cot(90o-) = tan, 1 + tan2 = sec2]

If A and B are the angles of a right angled triangle ABC, right angled at C, then 1+cot²A =

The correct option is B
sec²B

Given, triangle ABC is right angled at C. Therefore,

A+B=90^o or A=90^o-B

1+cot²A = 1 + cot²(90^o-B) = 1+tan²B = sec²B

[Since, cot(90^o-) = tan, 1 + tan² = sec²]